find the discriminant and the numbers of real roots for this equation: 4x^2+12x+9=0

Answer: [tex]D=0[/tex] The quadratic equation has one real root with a multiplicity of 2.Step-by-step explanation: Given a quadratic equation:  [tex]ax^2+bx+c=0[/tex] You can find the Discriminant with this formula: [tex]D=b^2-4ac[/tex] In this case you have the following quadratic equation: [tex]4x^2+12x+9=0[/tex] Where: [tex]a=4\\b=12\\c=9[/tex] Therefore, when you substitute these values into the formula, you get that the discriminant is this: [tex]D=(12)^2-4(4)(9)\\\\D=0[/tex] Since [tex]D=0[/tex], the quadratic equation has one real root with a multiplicity of 2 .