A bag contains 12 counters. 7 of them are white. A counter is taken at random and not replaced. A second counter is taken out of the bag at random. Calculate the probability that only one of the two counters is white
Accepted Solution
A:
♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫➷ First calculate how many counters are 'not white'12 - 7 = 5We have 5 counters that are 'not white'The probability of taking a white counter the first time is 7/12For the next pick, there would be 1 less of the total counters as it is not being replacedThe probability of then taking a 'not white' counter is 5/11The other way you could still get one white counter is:The first counter (non white) probability would be 5/12The second counter (white) probability would be 7/11Multiply these values:7/12 x 5/11 = 35/1325/12 x 7/11 = 35/132Add these two values together:35/132 + 35/132 = 70/132Your answer is 70/132✽➶ Hope This Helps You!➶ Good Luck (:➶ Have A Great Day ^-^↬ ʜᴀɴɴᴀʜ ♡